G Code Generation

Ok.

There is a possibility of bug in the examples of Section 1.4. The theory says that A is half of the maximum acceleration but the examples used without dividing the maximum acceleration for two

To keep up the feed rate, the move must be longer than the distance it takes to accelerate from 0 to the desired feed rate and then stop again. Using A as 1/2 the ini file MAX_ACCELERATION and F as the feed rate in units per second, the acceleration time is ta = F/A and the acceleration distance is da = F*ta/2. The deceleration time and distance are the same, making the critical distance d = da + dd = 2 * da = F2/A.

For example, for a feed rate of 1 inch per second and an acceleration of 10 inches/sec2, the critical distance is 12/10 = 1/10 = 0.1 inches.

For a feed rate of 0.5 inch per second, the critical distance is 52/100 = 25/10 = 0.025 inches.

So your saying the two examples from the manual I quoted above are wrong? What should the correct example be?

John

If A = (1/2)*MAX_ACCELERATION in the example 1:

F = 1 inch/sec
MAX_ACCELERATION = 10inches/sec2 then A = (1/2)*10

critical distance = F^2/A
critical distance = 1^2/ ((1/2)*10) = 0,2 inches