G93 Inverse Time Mode
Thanks
JT
Please Log in or Create an account to join the conversation.
I have never used G93, so I am not really qualified to comment, but that has never stopped me in the past.
As I understand it you need to calculate how long the segment should take, in minutes, based on path-length / speed.
Then the F-word is the inverse of that time.
Actually, you can miss a step, the F-word just needs to be (speed units/min) / (length in machine units).
I note that the docs state than an F-word is needed on every motion line.
Please Log in or Create an account to join the conversation.
JT
Please Log in or Create an account to join the conversation.
The person who wrote this seems to be
www.eng-tips.com/viewthread.cfm?qid=200454
F(code) = 1(minute) / (time = 3D distance/velocity)
The 3D distance of the move is calculated in model coordinate space at the NC control point, not in machine coordinate space and not necessarily at the tool tip. For example, a 5-inch move at 50 IPM takes 5 50ths of a minute, yielding an inverse time calculation of 1/.1 and an F-code of F10. The same 5-inch move at 700 IPM would be 1(minute) / (time = 5 / 700) or (1/(5/700)) or (1/.0071428) or F1400.168
That sort of makes sense to my long disused maths head
regards
PS Looks like you got plenty of answers on the users list
Once they get over the 'F Word' thing, you will probably get the same answer
Please Log in or Create an account to join the conversation.
F(code) = 1(minute) / (time = 3D distance/velocity)
Yes, but 1 / (x / y) is the same as y / x
So, there is no point doing 1 / ( distance / speed ), you can just calculate ( speed / distance ).
Please Log in or Create an account to join the conversation.