Testing the GPIO pins on 7i92t

With W1 and W2 removed the input pin states are
undefined until a pin is driven since you end up with
resistive connections between all pins per connector
if the pullup or pulldown resistor common is not
connected to either 5V (W1 or W2 up) or ground
(W1 or W2 down)

Basically, it makes no sense to run the card without
the W1 or W2 jumpers.

I believe I got it. 7i92t does not have isolated IO's on the same port. When I remove the W1/W2 jumper, two IOs located on the same port are still internally connected by their 4.7K resistors. Thank you, Peter.

Yes, if you disconnect the pullup/pulldown resistor common
(by removing W1 or W2) you would have a 9.4k  resistance
between any 2 IO pins.

(Instead of a 4.7K resistance to 5V or ground and no coupling
between pins if W1 and W2 are installed)