Help needed to get my 7i76E + 7i85S + 7i73 on my mill going.

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16 Aug 2018 14:22 #116159 by tecno
OK not 30 but 21 if I am correct but still many setp's ;)

GearShift Hi
Gear A 1501 to 2500 rpm
Gear B 1251 to 1500 rpm

GearShift Lo
Gear A 751 to 1250
Gear B 451 to 750
Gear C 271 to 450
Gear D 161 to 270
Gear E 80 to 160

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16 Aug 2018 14:28 #116161 by andypugh
So C D and E can't be used with High / Low ?

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16 Aug 2018 14:29 #116162 by andypugh
You might want to let the gear ratios overlap. Maybe 1240 shouldn't require a switch from B High to A low.

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16 Aug 2018 14:35 #116164 by tecno
With C D E in low gear only I get the whole range from 80 to 2500 with full torq.

But if there is no problems with overlapping so why not. The problem I see is how will LCNC determine what gears are most suitable? Max torq or less torq?

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16 Aug 2018 20:38 #116180 by pawel77
hello tecno,

it looks like your gears are set up by electrical contacts. why you do not allow linuxcnc to take in charge of that through output pins and relays. you chose your spindle speed and LCNC decide which gear to activate.

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16 Aug 2018 20:49 #116182 by tecno
Hello Pawel, the gearbox on my mill is totally manual. Only sensors on each gear setting connected to 7i76e inputs.

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17 Aug 2018 11:51 #116201 by tecno
Is this the way for setp?

setp hm2_7i76e.0.7i76.0.0.input-14-max-speed 160
setp hm2_7i76e.0.7i76.0.0.input-14-min-speed 80
setp hm2_7i76e.0.7i76.0.0.input-14-ratio ??????

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17 Aug 2018 14:17 #116202 by Hakan
I'll have a go at it. If its wrong I'm sure it will be corrected by those that know.

The gear max min and ratio pins belong to the gearblocker component.
And then is the question on where the index for the gear will go. I think it is
zero-based, so gear one is index zero. So if my ramblings are correct it could be like
# First gear
setp gearblocker.0.gear.0.min-speed 80
setp gearblocker.0.gear.0.max-speed 160
setp gearblocker.0.gear.0.ratio 0.1  
# Second gear
setp gearblocker.0.gear.1.min-speed 160
setp gearblocker.0.gear.1.max-speed 240
setp gearblocker.0.gear.1.ratio 0.4 
# and so on for all the gears

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17 Aug 2018 14:27 #116203 by tecno
Hmmm looking at .comp we have this

case 1: // Gear E
gear = (high_gear != 0) ? 5 : 10;
break;

Should it not be like this then? Hi gear is 5 and Lo gear is 10 right?

setp gearblocker.0.gear.10.min-speed 80

Sure somebody will correct us ;)

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17 Aug 2018 17:29 #116213 by tecno
Is this correct?
#GearShift Lo
# E gear
setp gearblocker.0.gear-E.min-speed 80
setp gearblocker.0.gear-E.max-speed 160
setp gearblocker.0.gear-E.ratio 0.064  
# D gear
setp gearblocker.0.gear-D.min-speed 160
setp gearblocker.0.gear-D.max-speed 270
setp gearblocker.0.gear-D.ratio 0.108 
# C gear
setp gearblocker.0.gear-C.min-speed 270
setp gearblocker.0.gear-C.max-speed 450
setp gearblocker.0.gear-C.ratio 0.18 
# B gear
setp gearblocker.0.gear-B.min-speed 450
setp gearblocker.0.gear-B.max-speed 750
setp gearblocker.0.gear-B.ratio 0.3 
# A gear
setp gearblocker.0.gear-A.min-speed 750
setp gearblocker.0.gear-A.max-speed 1250
setp gearblocker.0.gear-A.ratio 0.5 

#GearShift Hi
#B gear
setp gerablocker.0.high_gear.gear-B.min-speed 1250
setp gerablocker.0.high_gear.gear-B.max-speed 11500
setp gearblocker.0.high_gear.gear-B.ratio 0.6
#A gear
setp gerablocker.0.high_gear.gear-A.min-speed 1250
setp gerablocker.0.high_gear.gear-A.max-speed 11500
setp gearblocker.0.high_gear.gear-A.ratio 1

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