Hi,
I made a calculation to get the g-force when the machine is following the path of an arc.
- The formula : a = 4 π² r n²
reference
The above works for arc path's. But the next question is :
- how about straight corners, like line-line corners?
I think i have found a solution to calculate line-line corners changes, it has to be reviewed if
what i did is mathematical correct.
github source code
Imagine the following situation :
If you have 2 lines, with a 90 degree corner, speed 1000 mm/min, machine running along the path :
- lineA={0,0,0},{0,2,0}
- lineB={0,2,0},{2,2,,0}
Situation 1.
LineA & lineB are vectorized back to 0.1mm lenght, to get a really tight corner.
This will then result in ~37 revolutions/second at 1000mm/min when passing the corner.
the Gforce is then 0.37 [g]
Situation 2.
LineA & lineB are vectorized back to 0.01mm lenght. What would happen when passing the corner ?
the Gforce is then 3,7 [g]
hmm. exact 10 times more.
I think the conclusion is as follows :
When the machine can stop in 0.1mm at a speed of 1000mm/min the gforce = 0.37 [g]
When the machine can stop in 0.01mm at a speed of 1000mm/min the gforce = 3.7 [g]
For info, if the lineA & lineB where 3 arc points, the Gforce of moving along the arc is : 0.019 [g]
I will think about this solution and maybe ask review at math exchange. I must be sure this is
a realistic solution.
picture