PlasmaC Guide Voltage Divider Question for Mesa THCAD-10

dvn4life1972 wrote:
This would cut the voltage in half iirc (two equal resistors give half of input voltage). I thought it needed to be 0 to 10 volts at the card.

In this case that cuts the voltage by 21 fold.
And the "two equal resistors give half of input voltage" is very wrong. Resistance is calculated with regard to voltage that has to be dropped through it and the current passing through it. From those two values the power dissipated by the resistor can also be calculated.

Just for clarity, two equal resistors wired in parallel give half the resistance! Notice wired in parallel, not on different wires.

Thanks! As I said before, I absolutely know I'm ignorant about these things. I saw somewhere else online that statement about the half output voltage thing.

You are welcomed, always.
And no worries abut that, i was pretty sure you read that on the net, frankly i am getting tired of how much bad info is on the net, and this is the second time i am mentioning bad info today.
Another info on the resistance, just in case, putting two resistors together in parallel will half the resistance but it will double the voltage IF the current passing through them stays the same, but it never does, it will also go up.
Again, please do not worry about such things, we are here to help, and we do it gladly, so you are welcomed to ask anything, even stuff not related to CNC on the general discussion thread.

Thanks for the reply Rod! I based my decision in large part on information I read that you have posted (for the THCAD-10). I was hoping you would chime in.

I've read some of the primer recently as well, very nice repository of information and there's quite a bit there. At this point I believe I'm very near time to test motion...fingers crossed.

Pat

The resistors are in series regardless if they are all on one of the IN terminals of the THCAD or if they are split on both sides so it does not matter. YOu always sum resistors in series