Encoder ppr?
13 Jun 2018 07:25 #112274
by billykid
Replied by billykid on topic Encoder ppr?
I used these:
HEDR-55L2-BY07 3600 ppr 14400 cpr. with the 7i40 hbridge the positioning accuracy is + or - 0.001 mm, which is not possible with an encoder with less resolution I think.
closed loop servo-thread 8khz
pay attention, however, that the maximum frequency of these encoders is 320 khz,
for me it's fine because I go to more than 100 mm / s
regards
Mauro
HEDR-55L2-BY07 3600 ppr 14400 cpr. with the 7i40 hbridge the positioning accuracy is + or - 0.001 mm, which is not possible with an encoder with less resolution I think.
closed loop servo-thread 8khz
pay attention, however, that the maximum frequency of these encoders is 320 khz,
for me it's fine because I go to more than 100 mm / s
regards
Mauro
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13 Jun 2018 09:12 #112276
by CNCDoc
Replied by CNCDoc on topic Encoder ppr?
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13 Jun 2018 09:26 #112278
by andypugh
Replied by andypugh on topic Encoder ppr?
I am not clear if the "highest frequency response" refers to the maximum count rate or to the acceleration tracking rate. If these are simple optical encoders then it is unambiguous, but the magnetic ones seem to run a dpll internally and _that_ has limited bandwidth.
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13 Jun 2018 09:30 #112279
by tecno
Replied by tecno on topic Encoder ppr?
CALT 3600ppr 5000 pulse 6mm shaft servo flange optical encoder
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18 Oct 2024 13:07 #312502
by rajsekhar
I do not understand why 180kHz is multiplied by 4.
Replied by rajsekhar on topic Encoder ppr?
I get 3600PPR @3000 RPM = 50 RPS* 3600 = 180 KHz A/B signals and 720 KHz count rate (4X 180KHz)
at 5 mm/turn and 4X3600 counts per turn that's ~0.347 microns per count
I do not understand why 180kHz is multiplied by 4.
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18 Oct 2024 14:42 - 18 Oct 2024 14:56 #312519
by PCW
Replied by PCW on topic Encoder ppr?
The count rate is 4X the A or B frequency because
in (normal 4X) quadrature all edges of the A and B
signals are counted.
When you measure frequency you measure the number
of cycles per second, where each cycle has a rising and
falling edge, so the number of edges per cycle is double
the number of cycles. When you do this on both A and B,
you end up with 4 edges per cycle.
in (normal 4X) quadrature all edges of the A and B
signals are counted.
When you measure frequency you measure the number
of cycles per second, where each cycle has a rising and
falling edge, so the number of edges per cycle is double
the number of cycles. When you do this on both A and B,
you end up with 4 edges per cycle.
Last edit: 18 Oct 2024 14:56 by PCW.
The following user(s) said Thank You: rajsekhar
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