"Origami" CNC Plasma Build - folding 1200 x 600mm cut area

Did some more thinking and decided I liked the idea of the X drive being in vertical orientation.  Thing this has got enough legs to start making it. But do need to ponder possible drag chain mounting point.

 
 

That works just fine and i like the idlers being very near the beam and from above so the belt is safer from accidental grabs. Also if later you want to add another belt glued to the beam and do "servo belt" style motion, it is already set up!
Do you have the pulleys already? I buy them from "ideaformer1" on ebay, never had issues and you can get 60T + 20T + 200mm GT2 belt for something like 5$ a set. Can't beat that!

Have the pulleys and belt. Got a 4-lead (2mm pitch) 8mm leadscrew on the way for Z and still waiting for limit/home sensors.

Machine torch turned up this week so need to startt thinking about how to get that all working with the Cutskill 60.

Busy busy busy. 

Cheers - J.

Been a busy CAD day as I flesh out the X and Z designs.   Side views of the two mounting positions possible for standard sheet work or "tube" work up ~160mm diameter.  Of course with the bracket system I could increase that in the future by creating new/taller brackets.

Standard mount.
 

High clearance mount
 

One question for those following along and any who have “been there, done that”, is the single 15mm linear rail with that single truck/bearing going  to handle the loads in play during motion with that assembly on it?

As a reminder the gantry supports a cutting distance of 1260mm. Overall length of the beam is 1522mm. 

Should I be considering changes to support 2 trucks?  Or dual rails?  Or am I starting to worry about nothing?

I would appreciate thoughts from anyone more familiar with the engineering and load performance of these sorts of things. 

Cheers - James.  

Well, that is not hard too determine. The HGR specs (found on their dimensional diagrams) include torque specs for Mr, Mp and My. These  are 0.15 or 0.17 kNm (150 or 170 Nm) depending on the direction of the rotation about the carriage.

Force from inertia = m x a
So say your assembly weighs 5 kg and your acceleration is 3 m/sec/sec, your inertial force  equals 15  N

If you were to use CAD to define the centre of gravity of your assembly, you could define the rotational torque applied. Lets say your CoG was 100mm (0.1m) from the linear rail, the torque would be 15 * 0.1 = .15 Nm, about 1% of the HGR spec.

So at a guess, you have nothing to worry about